document.write( "Question 88727: can you please assist me with the following problems
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document.write( "1. use elimination to solved\r
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document.write( "x/3+4y=30
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document.write( "2x-y=5\r
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document.write( "6x-y/4=-9
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document.write( "3x+2y=-30\r
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document.write( " use subsitution to solved
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document.write( "y=x2+2x-2
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document.write( "y=3x+4 \n" );
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Algebra.Com's Answer #64503 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! 1)x/3+4y = 30......eq'n(1) \n" ); document.write( " 2x-y = 5 ........eq'n(2) \n" ); document.write( " multiply eq'n(1) by 3 throughout we get x+12y = 90 hence x = 90-12y \n" ); document.write( " substitute for x in eq'n (2) we get 2(90-12y)-y = 5 \n" ); document.write( " 180- 24y-y = 5 \n" ); document.write( " 180-5 = 25y \n" ); document.write( " 25y = 175 or y = 175/25 \n" ); document.write( " y = 7 \n" ); document.write( " substitute for y in 2x-y = 5 \n" ); document.write( " 2x = 5+y = 5+7 = 12 i.e,x = 12/2 = 6 \n" ); document.write( " the solution for the eq'ns are x = 6 and y = 7\r \n" ); document.write( "\n" ); document.write( " 2)6x-y/4 = -9........eq'n (1) \n" ); document.write( " 3x+2y = -30........eq'n(2)\r \n" ); document.write( "\n" ); document.write( " multiply eq'n (1) by 4 throughout we get 24x-y = -36 \n" ); document.write( " 24x+36 = y \n" ); document.write( " substitute for y in eq'n(2) we get 3x+2(24x+36) = -30 \n" ); document.write( " 3x+48x+72= -30 \n" ); document.write( " 51x = -30-72 = -102 \n" ); document.write( " x = -102/51 = -2 \n" ); document.write( " substituting for x in 3x+2y =-30 we get 3(-2)+2y = -30 \n" ); document.write( " -6 +2y -30 or 2y = -30+6 = -24 \n" ); document.write( " y = -24/2 = -12 \n" ); document.write( " the solution for the eq'ns is x = -2 and y = -12\r \n" ); document.write( "\n" ); document.write( " 3)y = x^2+2x-2.........eq'n (1) \n" ); document.write( " y = 3x+4 ............eq'n(2) \n" ); document.write( " substituting the value of y from eq'n(2) in eq'n(1) \n" ); document.write( " we get 3x+4 = x^2+2x-2 or x^2+2x-3x-2-4 = 0 \n" ); document.write( " x^2-x-6 = 0 spilliting -6 = -3*+2 \n" ); document.write( " x^2-3x+2x-6=0 \n" ); document.write( " x(x-3)+2(x-3) = 0 \n" ); document.write( " (x-3).(x+2) = 0 or x-3 = 0, x=3 \n" ); document.write( " x+2 = 0 , x = -2 \r \n" ); document.write( "\n" ); document.write( " if x=-2then value of y = 3(-2)+4 = -6+4 = -2 \n" ); document.write( " if x = 3 then the value of y = 3(3)+4 = 9+4 = 13\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |