document.write( "Question 1030117: solve by substitution x=y-1, the second part of the equation is 4x+y=12 answer with (___,___) \n" ); document.write( "
Algebra.Com's Answer #645019 by stanbon(75887)\"\" \"About 
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solve by substitution x=y-1, the second equation is 4x+y=12
\n" ); document.write( " answer with (___,___)
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\n" ); document.write( "Substitute for \"x\" and solve for \"y\"::
\n" ); document.write( "4(y-1) + y = 12
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\n" ); document.write( "5y - 4 = 12
\n" ); document.write( "5y = 16
\n" ); document.write( "y = 3 1/5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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