document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12669>Question 12669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I simplify the problem:<BR>\n" );
document.write( "ln(x+2)+ln3=ln39<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6450 by </B><A HREF=/tutors/aboutme.mpl?userid=AdolphousC><B>AdolphousC(70)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AdolphousC><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6450\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln(x+2)+ln3=ln39\r<BR>\n" );
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document.write( "You should be able to use the product property to rewrite the problem as follows\r<BR>\n" );
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document.write( "ln 3(x+2) = ln 39\r<BR>\n" );
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document.write( "the if the ln 3(x+2) = ln 39 then 3(x+2) = 39\r<BR>\n" );
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document.write( "now solve like normal<BR>\n" );
document.write( "3x + 6 = 39<BR>\n" );
document.write( "3x = 33<BR>\n" );
document.write( "x = 11 </SPAN>\n" );
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