document.write( "Question 1029807: An auditor for American Health Insurance reports that 20% of policyholders submit a claim during the year. 15 policyholders are selected randomly. What is the probability that at least 3 of them submitted a claim the previous year? \n" ); document.write( "
Algebra.Com's Answer #644981 by mathmate(429)\"\" \"About 
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\n" ); document.write( "Question:
\n" ); document.write( "An auditor for American Health Insurance reports that 20% of policyholders submit a claim during the year. 15 policyholders are selected randomly. What is the probability that at least 3 of them submitted a claim the previous year?
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\n" ); document.write( "Solution:
\n" ); document.write( "The probability of success (submitted a claim) is p=0.20, and remains constant throughout.
\n" ); document.write( "Size of sample, n=15, and policyholders are selected randomly (assumed independently as well).
\n" ); document.write( "x=3, number of successes for which probability is required.
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\n" ); document.write( "The above data satisfies the necessary conditions for modelling with the binomial distribution, which estimates the probability of x successes out of n each with a probability of p as:
\n" ); document.write( "P(X=x,p,n)=\"C%28n%2Cx%29%2Ap%5E%28x%29%2A%281-p%29%5E%28n-x%29\"
\n" ); document.write( "where
\n" ); document.write( "x=3
\n" ); document.write( "n=15
\n" ); document.write( "p=0.2 and
\n" ); document.write( "C(n,x)=n!/(x!(n-x)!) is the number of combinations for x objects chosen from n.
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\n" ); document.write( "Hence
\n" ); document.write( "P(X=x,p,n)=\"C%28n%2Cx%29%2Ap%5E%28x%29%2A%281-p%29%5E%28n-x%29\"
\n" ); document.write( "=\"C%2815%2C3%29%2A0.2%5E3%2A0.8%5E12\"
\n" ); document.write( "=455*0.008*0.0687195
\n" ); document.write( "=0.25014
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\n" ); document.write( "For more explanations on the conditions required to model with binomial distributions, and more examples, see:
\n" ); document.write( "http://www.euclid.host-ed.me/probability/binomialDistribution.html
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