document.write( "Question 1030026: p(z>c)=.2546 \n" ); document.write( "
Algebra.Com's Answer #644980 by mathmate(429) You can put this solution on YOUR website! \n" ); document.write( "Question: \n" ); document.write( "p(z>c)=.2546 \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "Z is a standard normal variable usually available on calculators or standard tables. The function has a domain of (-∞,+∞), and it looks like the following: \n" ); document.write( "The value of c can be read as 0.6601. \n" ); document.write( " \n" ); document.write( "In the case of a table, which are normally given to the left tail, as shown: \n" ); document.write( "http://isites.harvard.edu/fs/docs/icb.topic1499785.files/Public%20Domain%20Normal%20Distribution%20Table.pdf \n" ); document.write( " \n" ); document.write( "Since we need the right tail (Z>c), we subtract the value 0.2546 from one to get 0.7454, and look up the value from the table, which corresponds to the value 0.66, as shown in red. \n" ); document.write( " \n" ); document.write( "It is possible to calculate the value to a higher precision using statistical software such as R. The commands to use could be: \n" ); document.write( "qnorm(0.2546,lower.tail=FALSE); \n" ); document.write( "or \n" ); document.write( "qnorm(1-0.2546) \n" ); document.write( "for the same reasons as explained using the table. \n" ); document.write( "The latter statement makes use of the fact that the upper tail is the complement of the lower, hence subtract from one. \n" ); document.write( "The result R gives is 0.6600839, as follows:\r \n" ); document.write( "\n" ); document.write( "> qnorm(0.2546,lower.tail=FALSE) \n" ); document.write( "[1] 0.6600839 \n" ); document.write( "> qnorm(1-0.2546) \n" ); document.write( "[1] 0.6600839 \n" ); document.write( "> \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |