document.write( "Question 1030025: Write and solve a system of equations for a total of $15,000 invested in two accounts, with simple interest rates 1.85% and 2.95% respectively, where the total interest earned was $425. \n" ); document.write( "
Algebra.Com's Answer #644979 by mananth(16946)\"\" \"About 
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Part I 1.85% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 2.95% per annum ------------ Amount invested = y
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\n" ); document.write( "Interest----- 425
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\n" ); document.write( "Part I 1.85% per annum ---x
\n" ); document.write( "Part II 2.95% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 15000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "1.85% x + 2.95% y= 425
\n" ); document.write( "Multiply by 100
\n" ); document.write( "1.85 x + 2.95 y= 42500.00 --------2
\n" ); document.write( "Multiply (1) by -1.85
\n" ); document.write( "we get
\n" ); document.write( "-1.85 x -1.85 y= -27750.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 1.10 y= 14750
\n" ); document.write( "divide by 1.1
\n" ); document.write( " y = 13409.09
\n" ); document.write( "Part I 1.85% $ 1590.91
\n" ); document.write( "Part II 2.95% $ 13409.09
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\n" ); document.write( "CHECK
\n" ); document.write( "1590.91 --------- 1.85% ------- 29.43
\n" ); document.write( "13409.09 ------------- 2.95% ------- 395.57
\n" ); document.write( "Total -------------------- 425.00
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\n" ); document.write( "m.ananth@hotmail.ca
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