document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030061>Question 1030061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular swimming pool has a diagonal length of square root 68 meters and a length that is 6 more meters than width. find the dimensions and area of an entire pool </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644969 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call its width, x.  That means the length is x+6.<BR>\n" );
document.write( "Now we apply the Pythagorean Theorem:<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "x^2 + (x+6)^2 = (sqrt(68))^2<BR>\n" );
document.write( "x^2 + x^2 + 12x + 36 = 68<BR>\n" );
document.write( "2x^2 + 12x - 32 = 0<BR>\n" );
document.write( "x^2 + 6x - 16 = 0<BR>\n" );
document.write( "Now factor and solve<BR>\n" );
document.write( "(x + 8)(x - 2) = 0<BR>\n" );
document.write( "x = -8 (not possible)<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x = 2 meters (width) so that the length is<BR>\n" );
document.write( "x+6 = 8 meters </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );