document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029987>Question 1029987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Word Problem: it takes vince 9 minutes to mow the lawn if he works alone. If phil helps they can get the lawn mowed in 5 minutes. How long would it take phil to mow the lawn working alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644925 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here is my approach - others may have a different method. When I think of rate, it's \"miles per hour\" or \"units per time\" \r<BR>\n" );
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document.write( "Vince can mow 6-2/3 lawns per hour. (60/9 = 6.667)\r<BR>\n" );
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document.write( "Vince + Phil mow 12 lawns per hour. (60/5 = 2)\r<BR>\n" );
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document.write( "So it's simple subtraction, Phil can mow 5-1/3 lawns in 1 hour. And 60/5.33= 11.25 or 11-1/4 minutes to mow one.  </SPAN>\n" );
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