document.write( "Question 1029981: an experiment requires mixing a 40% acid solution with a 70% avid solution to create 150 ml of 46% acid solution. how much 40% acid solution and how much 70% acid solution should be used?
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Algebra.Com's Answer #644885 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let

represent the amount of 40% solution. Then the amount of 70% solution must be

. The amount of pure acid in the 40% solution is then

and the amount of pure acid in the 70% solution is

. The amount of pure acid in the 46% solution is

. Therefore:\r
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and then calculate

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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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