document.write( "Question 1029942: Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the given conditions.\r
\n" ); document.write( "\n" ); document.write( "zero of 2 and zero of 4 having multiplicity 2; f(1)=-18
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Algebra.Com's Answer #644869 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Zeros are 2 and 4 and 4 again.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=k%28x-2%29%28x-4%29%5E2\", which takes care of the zeros.
\n" ); document.write( "\"f%28x%29=k%28x-2%29%28x%5E2-8x%2B16%29\"
\n" ); document.write( "\"k%28x%5E3-8x%5E2%2B16x-2x%5E2%2B16x-32%29\"
\n" ); document.write( "\"highlight%28k%28x%5E3-10x%5E2%2B32x-32%29%29\", and then seems your choice to multiply through by k or not.\r
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\n" ); document.write( "\n" ); document.write( "Finding k should be easier using the fully factored form.
\n" ); document.write( "\"f%281%29=k%281-2%29%281-4%29%5E2=-18\"
\n" ); document.write( "\"k%28-1%29%28-3%29%5E2=-18\"
\n" ); document.write( "\"k%28-1%29%2A9=-18\"
\n" ); document.write( "\"k=2\"\r
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\n" ); document.write( "\n" ); document.write( "Now you can multiply through using k=2.
\n" ); document.write( "\"highlight%28highlight%28f%28x%29=2x%5E3-20x%5E2%2B64x-64%29%29\"
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