document.write( "Question 88735: how do i evaluate an expression meaning two to the power of eight over two to the power of three \n" ); document.write( "
Algebra.Com's Answer #64482 by jim_thompson5910(35256)\"\" \"About 
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\"2%5E8%2F2%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "When you divide common bases with exponents, you subtract the exponents\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E8%2F2%5E3=2%5E%288-3%29=2%5E5=32\"\r
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\n" ); document.write( "\n" ); document.write( "Notice that \"2%5E8%2F2%5E3\" really looks like\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E8%2F2%5E3=%282%2A2%2A2%2A2%2A2%2A2%2A2%2A2%29%2F%282%2A2%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E8%2F2%5E3=%28cross%282%2A2%2A2%29%2A2%2A2%2A2%2A2%2A2%29%2Fcross%282%2A2%2A2%29\" When you divide, it's like you're taking away 3 \"2\"s from the numerator. So that is the reason why you subtract the exponents.\r
\n" ); document.write( "\n" ); document.write( "\"2%5E8%2F2%5E3=%28cross%282%2A2%2A2%29%2A2%2A2%2A2%2A2%2A2%29%2Fcross%282%2A2%2A2%29=2%5E5\" So you're left with 5 \"2\"s, or \"2%5E5\"
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