document.write( "Question 1029854: Please help me with this problem:
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document.write( "Let R be the region bounded by the x axis and the graph of y = tan x on the closed interval [0, pi/4]. Use the \"disk method\" to find the volume of the solid formed when R is revolved about the x axis. Evaluate the integral. \n" );
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Algebra.Com's Answer #644789 by Natolino1983(23)![]() ![]() ![]() You can put this solution on YOUR website! V=PI×INTREGAL FROM 0 to PI/4 (tg^2(x)dx).\r \n" ); document.write( "\n" ); document.write( " Tg^2(x) = 1 - sec^2(x).\r \n" ); document.write( "\n" ); document.write( "So the anti-derivative= x - tg(x).\r \n" ); document.write( "\n" ); document.write( "So V = PI×( PI/4 -tg(pi/4) - (0 - tg(0)) =(Pi^2 -4×Pi)/4 cubic units. \n" ); document.write( " |