document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029852>Question 1029852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangular parcel of ground has sides of lengths 725ft,  650ft and 575ft. Find the measure of the largest angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644787 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We will apply the law of cosines here.<BR>\n" );
document.write( "Realize the largest angle is always opposite the largest side.  Let's call it c.  Then we write (and solve for angle C)<BR>\n" );
document.write( "c^2 = a^2 + b^2 - 2ab cos C<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "cos C = (c^2 - a^2 - b^2)/-2ab = (725^2 - 650^2 - 575^2)/(-2*650*575) = .3043<BR>\n" );
document.write( "and <BR>\n" );
document.write( "angle C = 72.3 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );