document.write( "Question 1029847: Can't figure out how to set this problem up correctly\r
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document.write( "Doreen and Irena plan to leave their houses at the same time, roller blade towards each other, and meet for lunch after 4 hours on the road.\r
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document.write( "Doreen can maintain a speed of 9.9 miles per hour, which is 90% of Irena's speed.\r
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document.write( "If they meet exactly as planned, what is the distance between their houses? \n" );
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Algebra.Com's Answer #644780 by mananth(16946) You can put this solution on YOUR website!
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Doreen and Irena plan to leave their houses at the same time, roller blade towards each other, and meet for lunch after 4 hours on the road.\r \n" ); document.write( "\n" ); document.write( "Doreen can maintain a speed of 9.9 miles per hour, \r \n" ); document.write( "\n" ); document.write( "which is 90% of Irena's speed. \n" ); document.write( "Irena,s speed will be 9.9*100/90 \n" ); document.write( "Irena's speed = 11 mph\r \n" ); document.write( "\n" ); document.write( "Let the distance between their houses be x \n" ); document.write( "t=d/r\r \n" ); document.write( "\n" ); document.write( "they are moving towards each other. \n" ); document.write( "their rate together will be 11+9.9 = 20.9 mph \n" ); document.write( "t=4\r \n" ); document.write( "\n" ); document.write( "4 = x/20.9\r \n" ); document.write( "\n" ); document.write( "x= 83.6 miles\r \n" ); document.write( "\n" ); document.write( "the distance between their houses is 83.6 miles\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If they meet exactly as planned, what is the distance between their houses? \n" ); document.write( " |