document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029847>Question 1029847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can't figure out how to set this problem up correctly\r<BR>\n" );
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document.write( "Doreen and Irena plan to leave their houses at the same time, roller blade towards each other, and meet for lunch after 4 hours on the road.\r<BR>\n" );
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document.write( "Doreen can maintain a speed of 9.9 miles per hour, which is 90% of Irena's speed.\r<BR>\n" );
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document.write( "If they meet exactly as planned, what is the distance between their houses? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644779 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, one way to find the total distance between them is to look at how much distance each girl travels and add them together...remember that distance = rate times time...<BR>\n" );
document.write( "For Doreen, she covers a distance of (9.9)(4) = 39.6 miles.<BR>\n" );
document.write( "For Irena, her speed is 11 miles per hour (found in a separate calculation, Doreen = 9.9 = .9(Irena)), so that<BR>\n" );
document.write( "Irena covers (11)(4) = 44 miles<BR>\n" );
document.write( "Thus the total distance between them is<BR>\n" );
document.write( "39.6 + 44 = 83.6 miles.<BR>\n" );
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