document.write( "Question 1029803: A woman is 4times older than her daughter.6 years ago the product of their ages was 136.Find their present ages.\r
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document.write( "The width of a rectangle is twice its length.Its area is 162cm square.what are its dimensions \n" );
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Algebra.Com's Answer #644738 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Ydaughter,s age be X \n" ); document.write( "Mother.s age will be 4x\r \n" ); document.write( "\n" ); document.write( "6 years ago \n" ); document.write( "Daughter was X-6 years \n" ); document.write( "Mother was 4x-6 years\r \n" ); document.write( "\n" ); document.write( "The product of their ages\r \n" ); document.write( "\n" ); document.write( "(X-6)(4x-6) =136\r \n" ); document.write( "\n" ); document.write( "4x^2-24x-6x+36=136\r \n" ); document.write( "\n" ); document.write( "4x^2-30x+36=136\r \n" ); document.write( "\n" ); document.write( "4x^2-30x-100=0\r \n" ); document.write( "\n" ); document.write( "4x^2-40x+10x-100=0\r \n" ); document.write( "\n" ); document.write( "4x(X-10)+10(X-10)=0\r \n" ); document.write( "\n" ); document.write( "(4x+10)(X-10)=0\r \n" ); document.write( "\n" ); document.write( "Either 4x+10=0 or X-10=0\r \n" ); document.write( "\n" ); document.write( "So X= -10/4 or X=10\r \n" ); document.write( "\n" ); document.write( "Age cannot be negative\r \n" ); document.write( "\n" ); document.write( "Therefore X=10 , daughter,s age\r \n" ); document.write( "\n" ); document.write( "Mother,s age =4x => 4x10=40 years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |