document.write( "Question 1029771: Lilian has part of $9000 invested at 4% and the remainder at 6%. His annual return on each investment is the same. At what rate would she have to invest all her money to get the same interest?\r
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Algebra.Com's Answer #644717 by addingup(3677)\"\" \"About 
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Let x be the amount invested at 4%
\n" ); document.write( "0.04x+0.06(9,000-x) = annual return
\n" ); document.write( "0.04x+54-0.06x = annual return
\n" ); document.write( "-0.02x = -54
\n" ); document.write( "x = 2,700 This is the amount invested at 4%
\n" ); document.write( "9,000-2,700 = 6,300 is the amount invested at 6%
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\n" ); document.write( "2700/9000 = 30% is invested at 4%
\n" ); document.write( "100-30 = 70% is invested at 6%
\n" ); document.write( "0.30*0.04 = 0.012
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\n" ); document.write( "0.70*0.06 = 0.042
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\n" ); document.write( "Blended interest: 0.054
\n" ); document.write( "To get the same interest she'd have to invest all her money at 5.4%
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