document.write( "Question 88707: I am to solve the following equations (there are two).\r
\n" ); document.write( "\n" ); document.write( "#1. x2(that is supposed to be squared)+3x=0\r
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\n" ); document.write( "\n" ); document.write( "#2. x2(that is supposed to be squared)+7x+12=0\r
\n" ); document.write( "\n" ); document.write( "I tried doing the Zero Factor Porperty, but i am coming up with the wrong answers.
\n" ); document.write( "THank you in advance for your help!
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Algebra.Com's Answer #64469 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "I'm assuming you can solve these using any technique you want right?\r
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\n" ); document.write( "\n" ); document.write( "So let's use the quadratic formula to solve these quadratics\r
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\n" ); document.write( "\n" ); document.write( "#1\r
\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B3%2Ax=0\" (note: since the polynomial does not have a constant term, the 3rd coefficient is zero. In other words, c=0. So that means the polynomial really looks like \"x%5E2%2B3%2Ax%2B0=0\" notice \"a=1\", \"b=3\", and \"c=0\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+%283%29%5E2-4%2A1%2A0+%29%29%2F%282%2A1%29\" Plug in a=1, b=3, and c=0\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9-4%2A1%2A0+%29%29%2F%282%2A1%29\" Square 3 to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9%2B0+%29%29%2F%282%2A1%29\" Multiply \"-4%2A0%2A1\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+3%29%2F%282%2A1%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+3%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B+3%29%2F2\" or \"x+=+%28-3+-+3%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2F2\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=0\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=0\"\r
\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-6%2F2\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B3%2Ax\", we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-13%2C+10%2C+-13%2C+10%2C1%2Ax%5E2%2B3%2Ax%2B0%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the roots are \"x=0\" and \"x=-3\". This verifies our answer\r
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\n" ); document.write( "\n" ); document.write( "#2\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B7%2Ax%2B12=0\" ( notice \"a=1\", \"b=7\", and \"c=12\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+%287%29%5E2-4%2A1%2A12+%29%29%2F%282%2A1%29\" Plug in a=1, b=7, and c=12\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+49-4%2A1%2A12+%29%29%2F%282%2A1%29\" Square 7 to get 49\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+49%2B-48+%29%29%2F%282%2A1%29\" Multiply \"-4%2A12%2A1\" to get \"-48\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+1+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+1%29%2F%282%2A1%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+1%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B+1%29%2F2\" or \"x+=+%28-7+-+1%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-6%2F2\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\" Divide\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\"\r
\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-8%2F2\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=-4\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\" or \"x=-4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B7%2Ax%2B12\", we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-14%2C+7%2C+-14%2C+7%2C1%2Ax%5E2%2B7%2Ax%2B12%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and we can see that the roots are \"x=-3\" and \"x=-4\". This verifies our answer
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