document.write( "Question 1029571: Solve the equation for θ if 0° ≤ θ < 360°. (Enter your answers as a comma-separated list.)
\n" ); document.write( "2 sin θ + 1 = csc θ
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Algebra.Com's Answer #644640 by fractalier(6550) $\"\"$ $\"About$

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Okay, from
\n" ); document.write( "2 sin θ + 1 = csc θ
\n" ); document.write( "2 sin θ + 1 = 1/sin θ
\n" ); document.write( "Multiply by sin θ and get
\n" ); document.write( "2 sin^2 θ + sin θ = 1
\n" ); document.write( "2 sin^2 θ + sin θ - 1 = 0
\n" ); document.write( "Now factor and solve
\n" ); document.write( "(2 sin θ - 1)(sin θ + 1) = 0
\n" ); document.write( "so that
\n" ); document.write( "sin θ = 1/2 and θ = 30 and 150 degrees
\n" ); document.write( "AND
\n" ); document.write( "sin θ = -1 and θ = 270 degrees \n" ); document.write( "

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