document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77863>Question 77863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> martina leaves home at 9am, bicycling at a rate of 24mi/h. Two hours later, john leaves, driving at the rate of 48 mi/h. at what time will john catch up with martina? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64456 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24X=48(X-2)<BR>\n" );
document.write( "24X=48X-96<BR>\n" );
document.write( "24X-48X=-96<BR>\n" );
document.write( "-24X=-96<BR>\n" );
document.write( "X=-96-24<BR>\n" );
document.write( "X=4 IN HOURS AFTER 9:AM THEY WILL MEET @1:00 PM.<BR>\n" );
document.write( " </SPAN>\n" );
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