document.write( "Question 1029574: Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is necessary, round to the nearest tenth of a degree. Use your graphing calculator to verify the solution graphically.
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document.write( "10 cos θ + 13 tan θ = sec θ \n" );
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Algebra.Com's Answer #644556 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 10 cos θ + 13 tan θ = sec θ \n" ); document.write( "------ \n" ); document.write( "10cos + 13(sin/cos) = 1/cos \n" ); document.write( "--------------------------------------- \n" ); document.write( "10cos^2 + 13sin = 1 \n" ); document.write( "---------------------- \n" ); document.write( "10(1-sin^2) + 13sin = 1 \n" ); document.write( "---------------------- \n" ); document.write( "10 - 10sin^2 + 13sin = 1 \n" ); document.write( "------- \n" ); document.write( "10sin^2 - 13sin -9 = 0 \n" ); document.write( "----- \n" ); document.write( "(2sin+1)(5sin-9) = 0 \n" ); document.write( "----- \n" ); document.write( "Only acceptable solution:: \n" ); document.write( "sin(t) = -1/2 \n" ); document.write( "---- \n" ); document.write( "Ans:: t = (7/6)pi or t = (11/6)pi \n" ); document.write( "--------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |