document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88688>Question 88688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 2:00 p.m. two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other, how fast does each car go,of they meet at 5:00p.m.? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64454 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THEY MEET AFTER THREE HOURS FROM THE START & EACH TRAVEL FOR 3 HOURS. ONE TRAXELS @ X MPH & THE OTHER @ (X+10) MPH.<BR>\n" );
document.write( "240=3X+3(X+10)<BR>\n" );
document.write( "240=3X+3X+30<BR>\n" );
document.write( "6X=240-30<BR>\n" );
document.write( "6X=210<BR>\n" );
document.write( "X=210/6<BR>\n" );
document.write( "X=35 MPH FOR THE SLOWER CAR.<BR>\n" );
document.write( "35+10=45 MPH FOR THE FASTER CAR.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "240=3*35+3*45<BR>\n" );
document.write( "240=105+135<BR>\n" );
document.write( "240=240<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );