document.write( "Question 88678: After taking a math class a little too seriously Kelli decides that her happiness is a function of the number of books she buys and the number of movies she sees per month. In fact she decides that her happiness quotient is: H = M(B^2) where M is movies and B is books. She can buy books for $9 each on average and can get into movies for $6 if she goes to the matinee. So if she sees 3 movies and buys 2 books her happiness quotient is \r
\n" ); document.write( "\n" ); document.write( "H = 3(2^2) = 12. If she has $100 to spend, what’s the highest she can make her happiness quotient?\r
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Algebra.Com's Answer #64452 by stanbon(75887)\"\" \"About 
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After taking a math class a little too seriously Kelli decides that her happiness is a function of the number of books she buys and the number of movies she sees per month. In fact she decides that her happiness quotient is: H = M(B^2) where M is movies and B is books. She can buy books for $9 each on average and can get into movies for $6 if she goes to the matinee. So if she sees 3 movies and buys 2 books her happiness quotient is \r
\n" ); document.write( "\n" ); document.write( "H = 3(2^2) = 12. \r
\n" ); document.write( "\n" ); document.write( "If she has $100 to spend, what’s the highest she can make her happiness quotient?\r
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\n" ); document.write( "H = M(B^2)
\n" ); document.write( "Value EQUATION:
\n" ); document.write( "9b+6m = 100
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\n" ); document.write( "Solve for m and b
\n" ); document.write( "Multiples of 9 are 9,18,27,36,45,54,63,72,81,90
\n" ); document.write( "Multiples of 6 ore 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96
\n" ); document.write( "Find one from each set that approximates 100.
\n" ); document.write( "Also notice that the quotient has a B^2 factor so the higher the B
\n" ); document.write( "the higher the H.
\n" ); document.write( "9*10+1*9 = 100
\n" ); document.write( "B=10 and M=1
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\n" ); document.write( "So, H = 1*10^2 = 100
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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