document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029430>Question 1029430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need the exact value for sec(theta), if (-5,-1) is a point near theta<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644486 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I misread your problem as sec 0, which is equal to 1.\r<BR>\n" );
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document.write( "Assuming you are referring to the angle theta that meets with (-5,-1) with the usual convention, we have that <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \cos \theta = \frac{adj}{hyp} = \frac{-5}{\sqrt{26}}\"> so <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \sec \theta = -\frac{\sqrt{26}}{5}\">. </SPAN>\n" );
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