document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029427>Question 1029427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radius of a semi circle is 5 cm.A square is fitted inside the semi circle .Calculate the area of the square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644478 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644478\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you draw this, the side of the square on the diameter is symmetric from the center, and let each part be x.<BR>\n" );
document.write( "But the sides are now 2x each, so the vertical sides, extending to the semicircle, are 2x.  The diagonal is the radius, or 5 cm.  That is a right triangle.<BR>\n" );
document.write( "x^2+(2x)^2=5^2=25<BR>\n" );
document.write( "5x^2=25<BR>\n" );
document.write( "x^2=5<BR>\n" );
document.write( "x= +sqrt(5) cm.<BR>\n" );
document.write( "2x= 2sqrt(5) cm.<BR>\n" );
document.write( "The area of the square is twice x or [2(sqrt(5)]^2=4*5=20 cm^2 </SPAN>\n" );
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