document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88666>Question 88666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/3+(-5/6) + (-1/2) =?\r<BR>\n" );
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document.write( "{-27+14}=?\r<BR>\n" );
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document.write( "-1/2-(5/8)=?\r<BR>\n" );
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document.write( "-3.4-(7.6)=?\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64446 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/3+(-5/6)+(-1/2)=1/3-5/6-1/2<BR>\n" );
document.write( "now we need to find a common denominator for 3,6 & 2. 6 is the LCD.<BR>\n" );
document.write( "(1*2-5-3*1)/6=(2-5-3)/6=-6/6=-1<BR>\n" );
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document.write( "-27+14=-13<BR>\n" );
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document.write( "-1/2-5/8 the common denominator hjere is 8<BR>\n" );
document.write( "(-1*4-5)/8=(-4-5)/8=-9/8=-1 1/8<BR>\n" );
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document.write( "-3.4-7.6=-11 </SPAN>\n" );
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