document.write( "Question 1029359: Given that 3cos(x) + 2sec(x) + 5 = 0, find all the possible values of cosx and tan^2(x). I found the possible values of cos(x) which are -2/3 and -1 but I couldn't find the values for tan^2(x). \n" ); document.write( "
Algebra.Com's Answer #644417 by robertb(5830)\"\" \"About 
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\"3%2Fsecx+%2B+2secx+%2B+5+=+0\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%283%2B2sec%5E2%28x%29+%2B+5secx%29%2Fsecx+=+0\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%28%282secx+%2B3%29%28secx+%2B+1%29%29%2Fsecx+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Assuming \"secx+%3C%3E+0\", we get \r
\n" ); document.write( "\n" ); document.write( "secx = -3/2, or secx = -1\r
\n" ); document.write( "\n" ); document.write( "==> \"tan%5E2%28x%29+%2B+1+=+9%2F4\", or \"tan%5E2%28x%29+%2B+1+=+1\".\r
\n" ); document.write( "\n" ); document.write( "==> \"tan%5E2%28x%29=+5%2F4\", or \"tan%5E2%28x%29+=+0\".\r
\n" ); document.write( "\n" ); document.write( "Incidentally, when the value of tangent squared is 5/4 or 0, \"secx%3C%3E0\", hence these are the two valid values for \"tan%5E2%28x%29\".\r
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