document.write( "Question 1027798: Q1
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document.write( "Suppose that the random variable X has the following cumulative distribution function:
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document.write( "x -1 1 3 5
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document.write( "F(x) 1/4 1/2 3/4 1\r
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document.write( " Find the probability distribution of this random variable.
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document.write( " Find p(x<3),p(x ≥1 )
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document.write( " Find the mean of the random variable X.
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document.write( " Find the standard deviation of the random variable X.\r
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document.write( "Q2 \r
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document.write( "The cumulative distribution function of the random variable X is given by: \r
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document.write( "F(x)={0(1- 9/x^2 ) for3
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document.write( " compute p(X≤ 5) and p( 8< X )
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document.write( " Find the expected value for the random variable X. \r
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Algebra.Com's Answer #644388 by robertb(5830)![]() ![]() You can put this solution on YOUR website! Q1 \n" ); document.write( "Suppose that the random variable X has the following cumulative distribution function: \n" ); document.write( "x -1 1 3 5 \n" ); document.write( "F(x) 1/4 1/2 3/4 1 \n" ); document.write( "Find the probability distribution of this random variable. \n" ); document.write( "Find p(x<3),p(x ≥1 ) \n" ); document.write( "Find the mean of the random variable X. \n" ); document.write( "Find the standard deviation of the random variable X. \r \n" ); document.write( "\n" ); document.write( "The pdf should be as follows: \n" ); document.write( "x -1 1 3 5 \n" ); document.write( "p(x) 1/4 1/4 1/4 1/4 \n" ); document.write( "Hence it is discrete uniformly distributed. \n" ); document.write( "p(x<3) = p(-1) + p(1) = 1/2, as can be directly read off from the table for F(x). \n" ); document.write( "p(x ≥1) = 1 - 1/4 = 3/4, as can be read off again from the table for F(x). \n" ); document.write( "Mean is \n" ); document.write( "Variance is \n" ); document.write( "==> \n" ); document.write( " \n" ); document.write( " |