document.write( "Question 1029334: solve 2log X- log(X-2) =2 log 3 \n" ); document.write( "
Algebra.Com's Answer #644387 by ikleyn(52814)\"\" \"About 
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\n" ); document.write( "solve 2log X- log(X-2) =2 log 3
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document.write( "2*log(x) - log(x-2) = 2*log(3)  --->\r\n" );
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document.write( "\"log%28%28x%5E2%29%29\" - \"log%28%28x-2%29%29\" = \"log%28%283%5E2%29%29\"  --->\r\n" );
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document.write( "\"log%28%28x%5E2%2F%28x-2%29%29%29\" = \"log%28%289%29%29\"  --->\r\n" );
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document.write( "\"x%5E2%2F%28x-2%29\" = \"9\",           (next step is to multiply both sides by (x-2) to rid off the denominator)\r\n" );
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document.write( "\"x%5E2\" = \"9%2A%28x-2%29\"         (next step is to simplify)\r\n" );
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document.write( "\"x%5E2+-+9x+%2B+18\" = \"0\",       (next step is to factor the left side)\r\n" );
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document.write( "(x-3)*(x-6) = 0.\r\n" );
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document.write( "The roots of the last equation are  x = 3  and  x = 6.\r\n" );
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document.write( "They both satisfy the original equation. Check it !\r\n" );
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document.write( "Answer.  x = 3  and  x = 6.\r\n" );
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