document.write( "Question 1029331: log x = log 12- log (x+1) \n" ); document.write( "

Algebra.Com's Answer #644363 by ikleyn(52787) $\"\"$ $\"About$

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\n" ); document.write( "log x = log 12- log (x+1)
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document.write( "log(x) = log(12)- log (x+1)  --->\r\n" );
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document.write( "log(x) + log(x+1) = log(12)  --->\r\n" );
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document.write( "log(x*(x+1)) = log(12)  --->\r\n" );
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document.write( "x*(x+1) = 12  --->\r\n" );
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document.write( " =   --->\r\n" );
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document.write( "Factor left side\r\n" );
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document.write( "(x+4)*(x-3) = 0,\r\n" );
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document.write( "The roots of this equation are  x = -4,  and/or  x = 3.\r\n" );
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document.write( "Only  x = 3  fits due to logarithm.\r\n" );
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document.write( "Answer.  x = 3.\r\n" );
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