document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029298>Question 1029298</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two similar figures have areas of 56 sq in and 87 sq in. A side of the smaller figure is 12 in. Find the corresponding side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644354 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You could choose something more specific just for comfort.\r<BR>\n" );
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document.write( "Imagine you have rectangles.  One is length 12 and the other is unknown length, but you are given the rectangles are similar.\r<BR>\n" );
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document.write( "SMALL Rectangle<BR>\n" );
document.write( "dimensions 12 and x<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x=56 ALIGN=MIDDLE  ALT=\"12x=56\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "LARGE Rectangle<BR>\n" );
document.write( "dimensions 12k and kx<BR>\n" );
document.write( "; the k because this is a proportionality constant, because the length of the rectangles ARE IN PROPORTION because the two rectangles ARE SIMILAR.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12k%2Akx=87 ALIGN=MIDDLE  ALT=\"12k%2Akx=87\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Goal is to find 12k, which is the length for the corresponding side on the larger rectangle.<BR>\n" );
document.write( "The system to solve is this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%2812x=56%2C12x%2Ak%5E2=87%29 ALIGN=MIDDLE  ALT=\"system%2812x=56%2C12x%2Ak%5E2=87%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "from which you should see the substitution to do;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=56%2Ak%5E2=87 ALIGN=MIDDLE  ALT=\"56%2Ak%5E2=87\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k=sqrt%2887%2F56%29 ALIGN=MIDDLE  ALT=\"k=sqrt%2887%2F56%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The corresponding side length on the larger figure is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2Asqrt%2887%2F56%29 ALIGN=MIDDLE  ALT=\"12%2Asqrt%2887%2F56%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >; and you could rationalize the denominator and simplify if you want. </SPAN>\n" );
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