document.write( "Question 1029270: Evaluating tan(8pi/3) without using a calculator please \n" ); document.write( "
Algebra.Com's Answer #644326 by stanbon(75887)\"\" \"About 
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Evaluating tan(8pi/3) without using a calculator please.
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\n" ); document.write( "tan((8/3)pi) = tan(2pi + (2/3)pi)) = tan((2/3)pi)) = -tan(pi/3) = -sqrt(3)
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\n" ); document.write( "Stan H.
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