document.write( "Question 1029211: If someone can please help me with this, it will be a huge help, thank you.\r
\n" ); document.write( "\n" ); document.write( "1) Given that f(x)= 0.25x^2 - 0.125x - 12.25 has a root at x = -6.75, use the axis of symmetry to find the other root of the function.
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Algebra.Com's Answer #644317 by rothauserc(4718)\"\" \"About 
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1) f(x)= 0.25x^2 - 0.125x - 12.25 has a root at x = -6.75
\n" ); document.write( "Here is the graph of this equation
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\n" ); document.write( "\"+graph%28+300%2C+200%2C+-8.2%2C+8.7%2C+-12.50%2C+5%2C+0.25x%5E2+-+0.125x+-+12.25%29+\"
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\n" ); document.write( "the axis of symmetry is a vertical line intersecting the vertex
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\n" ); document.write( "we know that the x coordinate of the axis of symmetry is
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\n" ); document.write( "x = -b / 2a = -(-0.125) / (2(0.25)) = 0.25
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\n" ); document.write( "The root x = -6.75 is one of two zeros of f(x) - to find the other zero, we calculate the distance -6.75 is from the x coordinate of the vertex
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\n" ); document.write( "distance = |-6.75| + 0.25 = 7
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\n" ); document.write( "therefore the other root is at x = 7.25
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