document.write( "Question 1029211: If someone can please help me with this, it will be a huge help, thank you.\r
\n" ); document.write( "\n" ); document.write( "1) Given that f(x)= 0.25x^2 - 0.125x - 12.25 has a root at x = -6.75, use the axis of symmetry to find the other root of the function.
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Algebra.Com's Answer #644314 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=x%5E2%2F4-x%2F8-49%2F4\"
\n" ); document.write( "\"f%28x%29=%281%2F4%29%28x%5E2-x%2F2%2B1%2F16%29-49%2F4-1%2F64\"
\n" ); document.write( "\"f%28x%29=%281%2F4%29%28x-1%2F4%29%5E2-784%2F64-1%2F64\"
\n" ); document.write( "\"f%28x%29=%281%2F4%29%28x-1%2F4%29%5E2-785%2F64\"
\n" ); document.write( "So then the vertex occurs at \"x=1%2F4\", which is also the location of the axis of symmetry.
\n" ); document.write( "So then the other root occurs at,
\n" ); document.write( "\"x=1%2F4%2Babs%281%2F4-%28-6.75%29%29\"
\n" ); document.write( "\"x=1%2F4%2B7\"
\n" ); document.write( "\"x=7.25\"
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