document.write( "Question 88625: My teacher wants the to solve the set of problems, but her being in Florida on vacation does not help me in any form or fashion....Please help\r
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document.write( "log7 + log (n - 2) = log 6n\r
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document.write( "log516 - log52t = log52\r
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document.write( "log5m = log5125\r
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document.write( "logy = log16 + log49\r
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document.write( "log6(b2 + 2) + log62 = 2\r
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document.write( "log3(5x+5) - log3(x2 - 1) = 0\r
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document.write( "log2(x - 2) + 5 = 8 - log2 4
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Algebra.Com's Answer #64429 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! log7 + log (n - 2) = log 6n \n" ); document.write( "log (7(n - 2)) - log 6n = 0 \n" ); document.write( "log (7(n - 2)/6n) = 0 \n" ); document.write( "log ((7n - 14)/6n) = 0 \n" ); document.write( "(7n - 14)/6n = 10^0 = 1 \n" ); document.write( "7n - 14 = 6n \n" ); document.write( "n = 14 \n" ); document.write( " \n" ); document.write( "The main idea is this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I will do two more: \n" ); document.write( "log5m = log5125 \n" ); document.write( "5m = 5125 \n" ); document.write( "m = 1025 \n" ); document.write( "And: \n" ); document.write( "log2(x - 2) + 5 = 8 - log2 4 \n" ); document.write( "log2(x - 2) = 3 - log2 2^2 \n" ); document.write( "log2(x - 2) = 3 - 2*log2 2 \n" ); document.write( "log2(x - 2) = 3 - 2*1 \n" ); document.write( "log2(x - 2) = 1 \n" ); document.write( "x - 2 = 2^1 \n" ); document.write( "x = 4 \n" ); document.write( " |