document.write( "Question 88625: My teacher wants the to solve the set of problems, but her being in Florida on vacation does not help me in any form or fashion....Please help\r
\n" ); document.write( "\n" ); document.write( "log7 + log (n - 2) = log 6n\r
\n" ); document.write( "\n" ); document.write( "log516 - log52t = log52\r
\n" ); document.write( "\n" ); document.write( "log5m = log5125\r
\n" ); document.write( "\n" ); document.write( "logy = log16 + log49\r
\n" ); document.write( "\n" ); document.write( "log6(b2 + 2) + log62 = 2\r
\n" ); document.write( "\n" ); document.write( "log3(5x+5) - log3(x2 - 1) = 0\r
\n" ); document.write( "\n" ); document.write( "log2(x - 2) + 5 = 8 - log2 4
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Algebra.Com's Answer #64429 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
log7 + log (n - 2) = log 6n
\n" ); document.write( "log (7(n - 2)) - log 6n = 0
\n" ); document.write( "log (7(n - 2)/6n) = 0
\n" ); document.write( "log ((7n - 14)/6n) = 0
\n" ); document.write( "(7n - 14)/6n = 10^0 = 1
\n" ); document.write( "7n - 14 = 6n
\n" ); document.write( "n = 14
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\n" ); document.write( "The main idea is this:
\n" ); document.write( "\"log%2810%2Cx%29+-+log%2810%2Cx+-+1%29+=+log%2810%2Cx%2F%28x+-+1%29%29\"
\n" ); document.write( "\"log%2810%2Cx%29+%2B+log%2810%2Cx+-+1%29+=+log%2810%2Cx%28x+-+1%29%29\"
\n" ); document.write( "I will do two more:
\n" ); document.write( "log5m = log5125
\n" ); document.write( "5m = 5125
\n" ); document.write( "m = 1025
\n" ); document.write( "And:
\n" ); document.write( "log2(x - 2) + 5 = 8 - log2 4
\n" ); document.write( "log2(x - 2) = 3 - log2 2^2
\n" ); document.write( "log2(x - 2) = 3 - 2*log2 2
\n" ); document.write( "log2(x - 2) = 3 - 2*1
\n" ); document.write( "log2(x - 2) = 1
\n" ); document.write( "x - 2 = 2^1
\n" ); document.write( "x = 4
\n" ); document.write( "\"graph%28500%2C300%2C-2%2C6%2C-2%2C7%2Clog%282%2Cx+-+2%29+%2B+5%2C8+-+log%282%2C4%29%29\"
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