document.write( "Question 1029216: the first term of a geometric progression is 5 and the fifth term is 1280 and the common ratio is 4. \r
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\n" ); document.write( "IS THE ANSWER OF THE NTH TERM 4N+1?
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Algebra.Com's Answer #644288 by ikleyn(52782)\"\" \"About 
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\n" ); document.write( "the first term of a geometric progression is 5 and the fifth term is 1280 and the common ratio is 4. \r
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\n" ); document.write( "IS THE ANSWER OF THE NTH TERM 4N+1?
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document.write( "The expression of the nth term of ANY geometric progression is\r\n" );
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document.write( "   \"a%5Bn%5D\" = \"a%5B1%5D%2Ar%5E%28n-1%29\",\r\n" );
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document.write( "where \"a%5B1%5D\" is its first term and \"r\" is its common ratio.\r\n" );
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document.write( "In your case \"a%5B1%5D\" = 5  and  \"r\" = 4.\r\n" );
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document.write( "So, the expression of the nth term of YOURS geometric progression is\r\n" );
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document.write( "   \"a%5Bn%5D\" = \"5%2A4%5E%28n-1%29\".\r\n" );
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document.write( "IS THE ANSWER OF THE NTH TERM 4N+1? - NO.\r\n" );
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