document.write( "Question 1029190: You throw the rocket up in the air with an initial velocity of 50 feet per second, and the rocket leaves your hand 6 feet above the ground. if you catch it when it falls back to a height of 5 feet, how long was the rocket in the air? does the increase in initial velocity increase or decrease the air time of the rocket? \n" ); document.write( "
Algebra.Com's Answer #644277 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! You throw the rocket up in the air with an initial velocity of 50 feet per second, and the rocket leaves your hand 6 feet above the ground. if you catch it when it falls back to a height of 5 feet, how long was the rocket in the air? does the increase in initial velocity increase or decrease the air time of the rocket? \n" ); document.write( "------------ \n" ); document.write( "You didn't spec acceleration due to gravity. \n" ); document.write( "-32 ft/sec/sec is commonly used. \n" ); document.write( "------------ \n" ); document.write( "h(t) = gt^2/2 + vt + h0 where g is gravity, v = 50 ft/sec, h0 = 6 feet \n" ); document.write( "---- \n" ); document.write( "h(t) = -16t^2 + 50t + 6 : h(t) = height in feet, t = seconds \n" ); document.write( "Solve for t when h(t) = 5 \n" ); document.write( "h(t) = -16t^2 + 50t + 6 = 5 \n" ); document.write( "-16t^2 + 50t + 1 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------- \n" ); document.write( "Ignore the negative solution \n" ); document.write( "t =~ 3.145 seconds \n" ); document.write( " |