document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029201>Question 1029201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the first six terms of the sequence whose nth term is given as;\r<BR>\n" );
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document.write( " a^n   = (-1)n / 2n^2 -3<BR>\n" );
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document.write( "           <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644274 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Write the first six terms of the sequence whose nth term is given as; <BR>\n" );
document.write( "a(n) = (-1)^n / (2n^2 -3)<BR>\n" );
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document.write( "a(1) = -1/(2-3) = -1/-1 = 1<BR>\n" );
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document.write( "a(2) = (-1)^2/(2*4-3) = 1/5<BR>\n" );
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document.write( "a(3) = (-1)^3/(2(9)-3) = -1/15<BR>\n" );
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document.write( "etc.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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