document.write( "Question 1029205: Given that x / x-1 is the first term of a geometric progression and x^2 / x^2-1 is the second term of the progression, in terms of x determine the common ratio and the third term of the progression.
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Algebra.Com's Answer #644270 by stanbon(75887)\"\" \"About 
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Given that x / x-1 is the first term of a geometric progression and x^2 / x^2-1 is the second term of the progression, in terms of x determine the common ratio and the third term of the progression.
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\n" ); document.write( "r = [x^2/(x^2-1)]/[x/(x-1)]
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\n" ); document.write( "r = [x^2/(x^2-1)]
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\n" ); document.write( "r = x/(x+1)
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\n" ); document.write( "a(3) = [x/(x-1)]^2
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\n" ); document.write( "etc.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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