document.write( "Question 1029199: The first term of a geometric progression is 5 and the fifth term is 1280, the common ratio is 4 \r
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document.write( "Find the expression of the nth term?\r
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document.write( "Can someone explain this step by step please \n" );
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Algebra.Com's Answer #644266 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " The first term of a geometric progression is 5 and the fifth term is 1280, the common ratio is 4 \n" ); document.write( "Find the expression of the nth term? \n" ); document.write( "-------- \n" ); document.write( "a(1) = 5 \n" ); document.write( "r = 4 \n" ); document.write( "---- \n" ); document.write( "a(5) = 5*4^x = 1280 \n" ); document.write( "4^x = 256 \n" ); document.write( "x = 4 \n" ); document.write( "So the exponent of the common ratio is one-less than the number of the term. \n" ); document.write( "------ \n" ); document.write( "Ans: a(n) = 5*4^(n-1) \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |