document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029189>Question 1029189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The remainder when x^3+3x^2+mx+6 is divided by (x+2) is 14. The value of m is:\r<BR>\n" );
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document.write( "A. 3\r<BR>\n" );
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document.write( "B. 2<BR>\n" );
document.write( "C. 1<BR>\n" );
document.write( "D.-1<BR>\n" );
document.write( "E.-2\r<BR>\n" );
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document.write( "How can i tackle this question? working out would be very grateful! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644241 by </B><A HREF=/tutors/aboutme.mpl?userid=Natolino1983><B>Natolino1983(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Natolino1983><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(x)=x^3+3x^2+mx+6.<BR>\n" );
document.write( "P(-2) = -8+12-2m+6 =10-2m =14 then, 2m=-4, m=-2.\r<BR>\n" );
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document.write( "Obs:Remainder (P(x)/(x-a)) =P(a).\r<BR>\n" );
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document.write( "Answer is m=-2 (E) </SPAN>\n" );
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