document.write( "Question 1029186: 2=log3(x) \n" ); document.write( "
Algebra.Com's Answer #644239 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
y = log3(x) if and only if 3^y = x.\r
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\n" ); document.write( "\n" ); document.write( "in your problem, this becomes 2 = log3(x) if and only if 3^2 = x.\r
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\n" ); document.write( "\n" ); document.write( "this makes x = 9.\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes 2 = log3(9).\r
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\n" ); document.write( "\n" ); document.write( "you can confirm using your calculator.\r
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\n" ); document.write( "\n" ); document.write( "the log function of your calculator gives you log10 (log to the base of 10).
\n" ); document.write( "the ln function of your calculator gives you loge (log to the base of e).\r
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\n" ); document.write( "\n" ); document.write( "using the log function of your calculator, you get log3(9) = log(9)/log(3) = 2.\r
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\n" ); document.write( "\n" ); document.write( "using the ln function of your calculator, you get log3(9) = ln(9)/ln(3) = 2.\r
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\n" ); document.write( "\n" ); document.write( "try it yourself.\r
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\n" ); document.write( "\n" ); document.write( "your solution is x = 9.
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