document.write( "Question 88611This question is from textbook
\n" ); document.write( ": How do you find a solution of the exponential equation, correct to four decimals places.
\n" ); document.write( "20. 10^1-x = 6^x
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Algebra.Com's Answer #64417 by Earlsdon(6294)\"\" \"About 
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You can use logarithms to solve exponential equations.
\n" ); document.write( "\"10%5E%281-x%29+=+6%5Ex\" Take the commom logarthim of both sides.
\n" ); document.write( "\"Log%5B10%5D%2810%5E%28%281-x%29%29%29+=+Log%5B10%5D%286%5Ex%29\" Apply the power rule for logarithms.
\n" ); document.write( "\"%281-x%29Log%5B10%5D%2810%29+=+x%2ALog%5B10%5D%286%29\" Recall that \"Log%5B10%5D%2810%29+=+1\"
\n" ); document.write( "\"%281-x%29+=+x%2ALog%5B10%5D%286%29\" Add x to both sides.
\n" ); document.write( "\"1+=+x%2BxLog%5B10%5D%286%29\" Factor out the x.
\n" ); document.write( "\"1+=+x%281%2BLog%5B10%5D%286%29%29\" Divide both sides by \"1%2BLog%5B10%5D%286%29\"
\n" ); document.write( "\"1%2F%281%2BLog%5B10%5D%286%29%29+=+x\" Evaluate this.
\n" ); document.write( "\"1%2F%281%2B0.778%29+=+x\"
\n" ); document.write( "\"x+=+1%2F1.778\"
\n" ); document.write( "\"x+=+0.56243\"
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