document.write( "Question 1029126: find three consecutive odd integers such that 3 times the sum of all three is 28 more than the product of the first and second integers. \n" ); document.write( "

Algebra.Com's Answer #644167 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "Let $\"x\"$ , $\"%28x%2B2%29\"$ , $\"%28x%2B4%29\"$ represent the three consecutive odd integers. \r
\n" ); document.write( "\n" ); document.write( "if $\"3\"$ times the $\"sum\"$ of all three is $\"28\"$ more than the $\"product\"$ of the first and second integers, we have:\r
\n" ); document.write( "\n" ); document.write( " $\"3%28x%2B%28x%2B2%29%2B%28x%2B4%29%29=x%28x%2B2%29%2B28\"$ .....solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%28x%2Bx%2B2%2Bx%2B4%29=x%5E2%2B2x%2B28\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%283x%2B6%29=x%5E2%2B2x%2B28\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"9x%2B18=x%5E2%2B2x%2B28\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B2x-9x-18%2B28=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2-7x%2B10=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2-5x-2x%2B10=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28x%5E2-5x%29-%282x-10%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%28x-5%29-2%28x-5%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28x-5%29+%28x-2%29+=+0\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solutions:
\n" ); document.write( " $\"%28x-5%29+=+0\"$ -> $\"x=5\"$
\n" ); document.write( "or
\n" ); document.write( " $\"%28x-2%29+=+0\"$ -> $\"x=2\"$ ->even\r
\n" ); document.write( "\n" ); document.write( "so, your numbers are: $\"5\"$ , $\"7\"$ , $\"9\"$ \r
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