document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029126>Question 1029126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive odd integers such that 3 times the sum of all three is 28 more than the product of the first and second integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644162 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> They are x, x+2 and x+4.<BR>\n" );
document.write( "add them to get 3x+6<BR>\n" );
document.write( "3(3x+6) -28 = x (x+2)=x^2+2x<BR>\n" );
document.write( "9x+18-28=9x-10=x^2+2x<BR>\n" );
document.write( "x^2-7x+10=0<BR>\n" );
document.write( "(x-5)(x-2)=0<BR>\n" );
document.write( "x=5 and 2, but only 5 is odd.<BR>\n" );
document.write( "The numbers are 5,7,9<BR>\n" );
document.write( "They add to 21<BR>\n" );
document.write( "3*21-28=35<BR>\n" );
document.write( "That is the product of the first two integers. </SPAN>\n" );
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