document.write( "Question 1029035: The length of a rectangle is 3 centimeters less than its width. What are the dimensions of the rectangle if its area is 134 . \n" ); document.write( "
Algebra.Com's Answer #644139 by Alan3354(69443)\"\" \"About 
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The length of a rectangle is 3 centimeters less than its width. What are the dimensions of the rectangle if its area is 134 .
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\n" ); document.write( "L = W + 3
\n" ); document.write( "L*W = 134
\n" ); document.write( "w*(w+3) = 134
\n" ); document.write( "w^2 + 3w - 134 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B3x%2B-134+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%283%29%5E2-4%2A1%2A-134=545\".
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\n" ); document.write( " Discriminant d=545 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-3%2B-sqrt%28+545+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%283%29%2Bsqrt%28+545+%29%29%2F2%5C1+=+10.1726175299288\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%283%29-sqrt%28+545+%29%29%2F2%5C1+=+-13.1726175299288\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B3x%2B-134\" can be factored:
\n" ); document.write( " \"1x%5E2%2B3x%2B-134+=+%28x-10.1726175299288%29%2A%28x--13.1726175299288%29\"
\n" ); document.write( " Again, the answer is: 10.1726175299288, -13.1726175299288.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B3%2Ax%2B-134+%29\"

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\n" ); document.write( "W =~ 10.1726
\n" ); document.write( "L =~ 13.1726
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