document.write( "Question 88592: hi!
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\n" ); document.write( "\n" ); document.write( "a garden plot contain 200 sq. ft. if its length is to be twice its width, what should its dimensions be?
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Algebra.Com's Answer #64413 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
The area of the rectangular garden plot is given by:
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\n" ); document.write( "Area = Length * Width
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\n" ); document.write( "The problem tells you that the Length is to be two times the Width. If we call the Length L
\n" ); document.write( "and the Width W, then we can write:
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\n" ); document.write( "L = 2*W
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\n" ); document.write( "We can now substitute into the Area equation 2*W for Length and W for Width and 200 for
\n" ); document.write( "Area. With these substitutions the Area equation becomes:
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\n" ); document.write( "200 = (2*W) * (W)
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\n" ); document.write( "Multiplying out the right side results in:
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\n" ); document.write( "\"200+=+2W%5E2\"
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\n" ); document.write( "Divide both sides of this equation by 2 and the equation then becomes:
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\n" ); document.write( "\"100+=+W%5E2\"
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\n" ); document.write( "Then take the square root of both sides. The square root of 100 is 10, and the square root
\n" ); document.write( "of W squared is just W. So the equation is then:
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\n" ); document.write( "\"10+=+W\"
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\n" ); document.write( "You now know that the Width W is 10 ft and since the Length is twice the Width, the Length
\n" ); document.write( "must be 2*10 or 20 ft.
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\n" ); document.write( "So the answer to the problem is W = 10 ft and L = 20 ft.
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\n" ); document.write( "When the Length and Width are multiplied, the answer for the Area is 20*10 = 200 sq ft,
\n" ); document.write( "just as the problem said it should be, so the answers for L and W check OK.
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\n" ); document.write( "Hope this helps you to understand the problem.
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