document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1029049>Question 1029049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know how to use both elimination and substitution methods on the linear equation 8x-3y=-16<BR>\n" );
document.write( "                5x+2y=-41 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644087 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> elimination<BR>\n" );
document.write( "8x-3y=-16<BR>\n" );
document.write( "5x+2y=-41<BR>\n" );
document.write( "========= same as<BR>\n" );
document.write( "16x-6y=-32<BR>\n" );
document.write( "15x+6y=-123<BR>\n" );
document.write( "==========add these<BR>\n" );
document.write( "31x=-155<BR>\n" );
document.write( "x= -5<BR>\n" );
document.write( "-40-3y=-16<BR>\n" );
document.write( "-3y=24<BR>\n" );
document.write( "y= -8<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Substitution<BR>\n" );
document.write( "2y=-5x-41<BR>\n" );
document.write( "y=(-5/2)x-41/2<BR>\n" );
document.write( "substitute into other<BR>\n" );
document.write( "8x-3(-5/2)x+123/2<BR>\n" );
document.write( "8x+7.5x=-123/2 -32/2, because the second term on the right is -16<BR>\n" );
document.write( "15.5x=-155/2<BR>\n" );
document.write( "31x=-155<BR>\n" );
document.write( "x=-5<BR>\n" );
document.write( "and y again is -8.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );