document.write( "Question 1028963: A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each. \n" ); document.write( "
Algebra.Com's Answer #644026 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! You can think of this as one of them standing still \n" ); document.write( "and the other moving at the sum of their speeds \n" ); document.write( "3:40 minus 3:00 is 40 min \n" ); document.write( "Convert to hrs: \n" ); document.write( " \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "------------------------------ \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "---------------- \n" ); document.write( "The speed of the snail is 45 m/hr \n" ); document.write( "The speed of the turtle is 495 m/hr \n" ); document.write( "----------------- \n" ); document.write( "check answer: \n" ); document.write( "Equation for the snail: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Equation for the turtle: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "---------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |