document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028955>Question 1028955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The line ,L8, is perpendicular to 2x + y - 3 = 0,find the gradient of L8<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #644021 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=644021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The line ,L8, is perpendicular to 2x + y - 3 = 0,find the gradient of L8<BR>\n" );
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document.write( "Find slope of given line::<BR>\n" );
document.write( "y = -2x+3<BR>\n" );
document.write( "slope = -2<BR>\n" );
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document.write( "Slope of L8 (the perpendicular line) = 1/2<BR>\n" );
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document.write( "Answer:: Gradient = slope = 1/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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